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G.f.: 1/((1-5x)(1-10x)(1-12x)).
1

%I #15 Jun 13 2015 00:48:54

%S 1,27,499,7863,113731,1561647,20724139,268611543,3422947891,

%T 43073421567,536871293179,6642406690023,81708636139651,

%U 1000502412972687,12206022852156619,148472243708301303

%N G.f.: 1/((1-5x)(1-10x)(1-12x)).

%H Harvey P. Dale, <a href="/A020568/b020568.txt">Table of n, a(n) for n = 0..900</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (27,-230,600).

%F a(0)=1, a(1)=27, a(2)=499, a(n)=27*a(n-1)-230*a(n-2)+600*a(n-3) From _Harvey P. Dale_, May 22 2012

%F a(n) = 5*5^n/7 -10*10^n +72*12^n/7. - _R. J. Mathar_, Jun 30 2013

%t CoefficientList[Series[1/((1-5x)(1-10x)(1-12x)),{x,0,40}],x] (* or *) LinearRecurrence[{27,-230,600},{1,27,499},40] (* _Harvey P. Dale_, May 22 2012 *)

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_.