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a(n) = (12*n+1)^3.
1

%I #18 Sep 08 2022 08:44:43

%S 1,2197,15625,50653,117649,226981,389017,614125,912673,1295029,

%T 1771561,2352637,3048625,3869893,4826809,5929741,7189057,8615125,

%U 10218313,12008989,13997521,16194277,18609625,21253933,24137569,27270901,30664297,34328125,38272753

%N a(n) = (12*n+1)^3.

%H Vincenzo Librandi, <a href="/A017535/b017535.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4,-6,4,-1).

%F G.f.: (1 + 2193*x + 6843*x^2 + 1331*x^3)/(1-x)^4. - _Vincenzo Librandi_, May 26 2016

%F a(n) = 4*a(n-1) - 6*a(n-2) + 4*a(n-3) - a(n-4), for n>3. - _Vincenzo Librandi_, May 26 2016

%F a(n) = A000578(A017533(n)). - _Michel Marcus_, May 26 2016

%t Table[(12 n + 1)^3, {n, 0, 50}] (* _Vincenzo Librandi_, May 26 2016 *)

%o (Maxima) makelist( (12*n+1)^3 ,n,0,30); /* _Martin Ettl_, Oct 21 2012 */

%o (Magma) [(12*n + 1)^3: n in [0..40]]; // _Vincenzo Librandi_, May 26 2016

%Y Cf. A000578, A017533.

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_.