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a(n) = (10*n + 3)^2.
1

%I #21 Sep 08 2022 08:44:42

%S 9,169,529,1089,1849,2809,3969,5329,6889,8649,10609,12769,15129,17689,

%T 20449,23409,26569,29929,33489,37249,41209,45369,49729,54289,59049,

%U 64009,69169,74529,80089,85849

%N a(n) = (10*n + 3)^2.

%H Vincenzo Librandi, <a href="/A017306/b017306.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (3,-3,1).

%F G.f.: -(9 + 142*x + 49*x^2)/(x-1)^3. - _R. J. Mathar_, Mar 20 2018

%o (Magma) [(10*n+3)^2: n in [0..35]]; // _Vincenzo Librandi_, Jul 31 2011

%o (PARI) a(n)=(10*n+3)^2 \\ _Charles R Greathouse IV_, Jun 17 2017

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_