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a(n) = (10*n)^12.
1

%I #15 Sep 08 2022 08:44:42

%S 0,1000000000000,4096000000000000,531441000000000000,

%T 16777216000000000000,244140625000000000000,2176782336000000000000,

%U 13841287201000000000000,68719476736000000000000,282429536481000000000000,1000000000000000000000000

%N a(n) = (10*n)^12.

%H Vincenzo Librandi, <a href="/A017280/b017280.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_13">Index entries for linear recurrences with constant coefficients</a>, signature (13, -78, 286, -715, 1287, -1716, 1716, -1287, 715, -286, 78, -13, 1).

%t (10Range[0,10])^12 (* _Harvey P. Dale_, Jul 08 2011 *)

%o (Magma) [(10*n)^12: n in [0..10]]; // _Vincenzo Librandi_, Jul 29 2011

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_