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a(n) = (8*n+3)^3.
1

%I #12 Sep 08 2022 08:44:41

%S 27,1331,6859,19683,42875,79507,132651,205379,300763,421875,571787,

%T 753571,970299,1225043,1520875,1860867,2248091,2685619,3176523,

%U 3723875,4330747,5000211,5735339,6539203,7414875

%N a(n) = (8*n+3)^3.

%H Vincenzo Librandi, <a href="/A017103/b017103.txt">Table of n, a(n) for n = 0..10000</a>

%H <a href="/index/Rec#order_04">Index entries for linear recurrences with constant coefficients</a>, signature (4,-6,4,-1).

%F G.f.: (27+1223*x+1697*x^2+125*x^3)/(x-1)^4 . - _R. J. Mathar_, Jul 14 2016

%t Table[(8 n + 3)^3, {n, 0, 40}] (* _Bruno Berselli_, Sep 17 2015 *)

%o (Magma) [(8*n+3)^3: n in [0..30]]; // _Vincenzo Librandi_, Jul 12 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_.