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a(n) = (6*n + 2)^10.
3

%I #21 Mar 29 2022 02:54:58

%S 1024,1073741824,289254654976,10240000000000,141167095653376,

%T 1125899906842624,6278211847988224,27197360938418176,

%U 97656250000000000,303305489096114176,839299365868340224,2113922820157210624,4923990397355877376,10737418240000000000,22130157888803070976

%N a(n) = (6*n + 2)^10.

%H Vincenzo Librandi, <a href="/A016942/b016942.txt">Table of n, a(n) for n = 0..2000</a>

%H <a href="/index/Rec#order_11">Index entries for linear recurrences with constant coefficients</a>, signature (11,-55,165,-330,462,-462,330,-165,55,-11,1).

%F From _Amiram Eldar_, Mar 29 2022: (Start)

%F a(n) = A016933(n)^10 = A016934(n)^5 = A016937(n)^2.

%F a(n) = 2^10*A016786(n).

%F Sum_{n>=0} 1/a(n) = PolyGamma(9, 1/3)/21941965946880. (End)

%t (6*Range[0,20]+2)^10 (* _Harvey P. Dale_, Apr 24 2017 *)

%o (Magma) [(6*n+2)^10: n in [0..25]]; // _Vincenzo Librandi_, May 05 2011

%Y Cf. A016786, A016933, A016934, A016935, A016936, A016937, A016938, A016939, A016940, A016941.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_