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a(n) = (4n+1)^4.
1

%I #13 Apr 01 2019 10:44:17

%S 1,625,6561,28561,83521,194481,390625,707281,1185921,1874161,2825761,

%T 4100625,5764801,7890481,10556001,13845841,17850625,22667121,28398241,

%U 35153041,43046721,52200625,62742241,74805201,88529281,104060401,121550625,141158161,163047361

%N a(n) = (4n+1)^4.

%H <a href="/index/Rec#order_05">Index entries for linear recurrences with constant coefficients</a>, signature (5, -10, 10, -5, 1).

%t Table[(4n+1)^4,{n,0,100}] (* _Mohammad K. Azarian_, Jun 18 2016 *)

%t LinearRecurrence[{5,-10,10,-5,1},{1,625,6561,28561,83521},30] (* _Harvey P. Dale_, Apr 01 2019 *)

%K nonn,easy

%O 0,2

%A _N. J. A. Sloane_.