%I #19 Sep 08 2022 08:44:41
%S 1,23,379,5483,74227,966635,12282883,153544091,1897874803,23272609547,
%T 283754322787,3445398949499,41707911082579,503763046196459,
%U 6074569573223491,73159552048508507,880297079110607155
%N Expansion of 1/((1-2x)(1-9x)(1-12x)).
%H Vincenzo Librandi, <a href="/A016324/b016324.txt">Table of n, a(n) for n = 0..900</a>
%H <a href="/index/Rec">Index entries for linear recurrences with constant coefficients</a>, signature (23,-150,216).
%F From _Vincenzo Librandi_, Oct 09 2011: (Start)
%F a(n) = (168*12^n + 2^(n+1)- 5*3^(2*n+3))/35.
%F a(n) = 21*a(n-1) - 108*a(n-2) + 2^n.
%F a(n) = 23*a(n-1) - 150*a(n-2) + 216*a(n-3), n >= 3. (End)
%t CoefficientList[Series[1/((1-2x)(1-9x)(1-12x)),{x,0,20}],x] (* or *) LinearRecurrence[{23,-150,216},{1,23,379},20] (* _Harvey P. Dale_, Apr 08 2013 *)
%o (Magma) [(168*12^n +2^(n+1)-5*3^(2*n+3))/35 : n in [0..20]]; // _Vincenzo Librandi_, Oct 09 2011
%o (PARI) Vec(1/((1-2*x)*(1-9*x)*(1-12*x))+O(x^99)) \\ _Charles R Greathouse IV_, Sep 26 2012
%K nonn,easy
%O 0,2
%A _N. J. A. Sloane_
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