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A016244 Expansion of 1/((1-x)*(1-6*x)*(1-9*x)). 4

%I #18 Jan 31 2022 03:18:23

%S 1,16,187,1942,19033,180628,1681639,15470674,141251605,1283357680,

%T 11622778531,105040363246,947975408017,8547451504972,77021100541663,

%U 693754126856458,6247172473597069,56244864253707304

%N Expansion of 1/((1-x)*(1-6*x)*(1-9*x)).

%H G. C. Greubel, <a href="/A016244/b016244.txt">Table of n, a(n) for n = 0..1000</a>

%H <a href="/index/Rec#order_03">Index entries for linear recurrences with constant coefficients</a>, signature (16,-69,54).

%F a(n) = (1 - 96*6^n + 135*9^n)/40. - Neven Juric, Oct 22 2009

%F a(0)=1, a(1)=16, a(n) = 15*a(n-1) - 54*a(n-2) + 1. - _Vincenzo Librandi_, Feb 10 2011

%F E.g.f.: (1/40)*(exp(x) - 96*exp(6*x) + 135*exp(9*x)). - _G. C. Greubel_, Jan 30 2022

%t LinearRecurrence[{16,-69,54}, {1,16,187}, 41] (* _G. C. Greubel_, Jan 30 2022 *)

%o (PARI) Vec(1/((1-x)*(1-6*x)*(1-9*x)) + O(x^40)) \\ _Michel Marcus_, Sep 04 2017

%o (Magma) [(1 -96*6^n +135*9^n)/40: n in [0..40]]; // _G. C. Greubel_, Jan 30 2022

%o (Sage) [(1 -16*6^(n+1) +15*9^(n+1))/40 for n in (0..40)] # _G. C. Greubel_, Jan 30 2022

%Y Cf. A003464, A024346, A024347.

%K nonn

%O 0,2

%A _N. J. A. Sloane_

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Last modified April 23 10:29 EDT 2024. Contains 371905 sequences. (Running on oeis4.)