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a(n) = 23^(4*n + 1).
1

%I #15 Sep 08 2022 08:44:38

%S 23,6436343,1801152661463,504036361936467383,141050039560662968926103,

%T 39471584120695485887249589623,11045767571919545466173812409689943,

%U 3091058643093537522799545838540043339063,865004941741938633917747707002884268046728983

%N a(n) = 23^(4*n + 1).

%H Vincenzo Librandi, <a href="/A013818/b013818.txt">Table of n, a(n) for n = 0..100</a>

%H Tanya Khovanova, <a href="http://www.tanyakhovanova.com/RecursiveSequences/RecursiveSequences.html">Recursive Sequences</a>

%H <a href="/index/Rec#order_01">Index entries for linear recurrences with constant coefficients</a>, signature (279841).

%F a(n) = 279841*a(n-1). - _Harvey P. Dale_, Nov 15 2013

%t 23^(4*Range[0,20]+1) (* or *) NestList[279841#&,23,20] (* _Harvey P. Dale_, Nov 15 2013 *)

%o (Magma) [23^(4*n+1): n in [0..15]]; // _Vincenzo Librandi_, Jul 07 2011

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_