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a(n) = 14^(2*n + 1).
2

%I #22 Sep 08 2022 08:44:38

%S 14,2744,537824,105413504,20661046784,4049565169664,793714773254144,

%T 155568095557812224,30491346729331195904,5976303958948914397184,

%U 1171355575953987221848064,229585692886981495482220544

%N a(n) = 14^(2*n + 1).

%H Vincenzo Librandi, <a href="/A013719/b013719.txt">Table of n, a(n) for n = 0..200</a>

%H Tanya Khovanova, <a href="http://www.tanyakhovanova.com/RecursiveSequences/RecursiveSequences.html">Recursive Sequences</a>

%H <a href="/index/Rec#order_01">Index entries for linear recurrences with constant coefficients</a>, signature (196).

%F From _Philippe Deléham_, Nov 25 2008: (Start)

%F a(n) = 196*a(n-1), a(0)=14.

%F G.f.: 14/(1-196*x). (End)

%p seq(14^(2*n+1),n=0..11); # _Nathaniel Johnston_, Jun 25 2011

%o (Magma) [14^(2*n+1): n in [0..15]]; // _Vincenzo Librandi_, Jun 26 2011

%o (PARI) a(n)=14^(2*n+1) \\ _Charles R Greathouse IV_, Jul 11 2016

%Y Bisection of A001023 (14^n).

%Y Cf. A013708-A013718, A013720-A013729.

%K nonn,easy

%O 0,1

%A _N. J. A. Sloane_