%I #29 Apr 11 2024 11:37:43
%S 12,1,1,1,1,3,1,1,1,1,24,1,1,1,1,3,1,1,1,1,24,1,1,1,1,3,1,1,1,1,24,1,
%T 1,1,1,3,1,1,1,1,24,1,1,1,1,3,1,1,1,1,24,1,1,1,1,3,1,1,1,1,24,1,1,1,1,
%U 3,1,1,1,1,24,1,1,1,1,3,1,1
%N Continued fraction for sqrt(159).
%H G. Xiao, <a href="http://wims.unice.fr/~wims/en_tool~number~contfrac.en.html">Contfrac</a>
%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>
%H <a href="/index/Rec#order_10">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,0,0,1).
%p Digits := 100: convert(evalf(sqrt(N)),confrac,90,'cvgts'):
%t ContinuedFraction[Sqrt[159],300] (* _Vladimir Joseph Stephan Orlovsky_, Mar 23 2011 *)
%t PadRight[{12},120,{24,1,1,1,1,3,1,1,1,1}] (* _Harvey P. Dale_, Apr 11 2024 *)
%K nonn,cofr,easy
%O 0,1
%A _N. J. A. Sloane_