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Continued fraction for sqrt(153).
1

%I #28 Dec 23 2023 14:25:05

%S 12,2,1,2,2,2,1,2,24,2,1,2,2,2,1,2,24,2,1,2,2,2,1,2,24,2,1,2,2,2,1,2,

%T 24,2,1,2,2,2,1,2,24,2,1,2,2,2,1,2,24,2,1,2,2,2,1,2,24,2,1,2,2,2,1,2,

%U 24,2,1,2,2,2,1,2,24,2,1,2,2

%N Continued fraction for sqrt(153).

%H G. Xiao, <a href="http://wims.unice.fr/~wims/en_tool~number~contfrac.en.html">Contfrac</a>

%H <a href="/index/Con#confC">Index entries for continued fractions for constants</a>

%H <a href="/index/Rec#order_08">Index entries for linear recurrences with constant coefficients</a>, signature (0,0,0,0,0,0,0,1).

%t ContinuedFraction[Sqrt[153],300] (* _Vladimir Joseph Stephan Orlovsky_, Mar 23 2011 *)

%K nonn,cofr,easy

%O 0,1

%A _N. J. A. Sloane_