%I #10 Jan 01 2020 16:56:35
%S 1,12,2560,2903040,10701766656,98099527680000,1888892391260160000,
%T 68028459471234662400000,4210629057689788455321600000,
%U 419914246162041071241548267520000,64132357595657181789618280857600000000,14397414995889590911587619167220531200000000
%N a(n) = 4^n*(2*n+1)!*(n!)^2/(n+1).
%H Andrew Howroyd, <a href="/A010053/b010053.txt">Table of n, a(n) for n = 0..100</a>
%p 4^n*(2*n+1)!*(n!)^2/(n+1);
%t Table[(4^n (2n+1)! (n!)^2)/(n+1),{n,0,10}] (* _Harvey P. Dale_, Nov 04 2017 *)
%o (PARI) a(n) = {4^n*(2*n+1)!*(n!)^2/(n+1)} \\ _Andrew Howroyd_, Jan 01 2020
%K nonn,easy
%O 0,2
%A Joe Keane (jgk(AT)jgk.org)
%E Terms a(10) and beyond from _Andrew Howroyd_, Jan 01 2020