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# User:Thomas Baruchel

A continued fraction formula I found for the ${\displaystyle \tanh }$ function (see the link on math.stackexchange.com):
${\displaystyle \tanh z={\textrm {K}}_{n=1}^{\infty }{\frac {1+\left((n-1){\frac {\pi }{4}}z^{-1}\right)^{2}}{(2n-1){\frac {\pi }{4}}z^{-1}}}}$