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# Talk:N-bonacci numbers

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## 0-bonacci numbers

So what are 0-bonacci numbers, if there is such a thing? Alonso del Arte 17:20, 5 June 2012 (UTC)

Abiding by the following definition of N-bonacci numbers
The N-bonacci numbers arise from a recurrence relation like that of the Fibonacci numbers but with ${\displaystyle \scriptstyle N\,}$ initial terms ${\displaystyle \scriptstyle (a(n)\,=\,0,\,0\,\leq \,n\,\leq \,N-2;\;a(N-1)\,=\,1)\,}$ instead of two initial terms. Each subsequent term is the sum of the previous ${\displaystyle \scriptstyle N\,}$ terms.
we thus have no initial term, then sum of zero previous terms, giving the empty sum! (talk about degenerate!) This begets the all 0's sequence.
{0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, 0, ...}

0-bonacci numbers and 1-bonacci numbers (enanacci numbers) being degenerate N-bonacci numbers! — Daniel Forgues 02:56, 6 June 2012 (UTC)