OFFSET
1,3
COMMENTS
The leaders of strictly increasing runs in a sequence are obtained by splitting it into maximal strictly increasing subsequences and taking the first term of each.
The k-th composition in standard order (graded reverse-lexicographic, A066099) is obtained by taking the set of positions of 1's in the reversed binary expansion of k, prepending 0, taking first differences, and reversing again. This gives a bijective correspondence between nonnegative integers and integer compositions.
LINKS
EXAMPLE
The maximal strictly increasing subsequences of the 212th composition in standard order are ((1,2),(2,3)), with leaders (1,2), so 212 is in the sequence.
The terms together with corresponding compositions begin:
0: ()
1: (1)
2: (2)
4: (3)
5: (2,1)
6: (1,2)
8: (4)
9: (3,1)
12: (1,3)
16: (5)
17: (4,1)
18: (3,2)
20: (2,3)
22: (2,1,2)
24: (1,4)
26: (1,2,2)
MATHEMATICA
stc[n_]:=Differences[Prepend[Join @@ Position[Reverse[IntegerDigits[n, 2]], 1], 0]]//Reverse;
Select[Range[0, 100], UnsameQ@@First/@Split[stc[#], Less]&]
CROSSREFS
KEYWORD
nonn
AUTHOR
Gus Wiseman, Jul 27 2024
STATUS
approved