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A373386
Smallest integer m > 1 such that m == m^m (mod 10^(len(m) + n)), where len(m) is the number of digits of m.
0
5, 51, 751, 10001, 100001, 1000001, 10000001, 100000001, 1000000001
OFFSET
0,1
COMMENTS
By definition, this sequence is a subsequence of A082576.
It is not known if a(n) = 10^(n + 1) + 1 holds for all n >= 3.
EXAMPLE
a(2) = 751 since m = 751 is the smallest integer satisfying m == m^m (mod 10^(len(m) + 2)), given the fact that 751 is a 3-digit number and 751^751 == 500751 (mod 10^6) and thus 751^751 == 751 (mod 10^(3 + 2)).
PROG
(PARI) a(n) = my(im); for (len_m = 1, oo, if (len_m==1, im=2, im=10^(len_m - 1)); for (m = im, 10^len_m - 1, if (m == Mod(m, 10^(len_m + n))^m, return(m)))); \\ Michel Marcus, Jun 03 2024
CROSSREFS
KEYWORD
nonn,base,more
AUTHOR
Marco Ripà, Jun 02 2024
EXTENSIONS
a(7)-a(8) from Michel Marcus, Jun 03 2024
STATUS
approved