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a(n) = (n!)!/((n-1)!)!.
0

%I #6 Jul 19 2024 19:15:42

%S 1,1,2,360,861733891296165888000

%N a(n) = (n!)!/((n-1)!)!.

%C a(5) has 177 digits.

%t a[0] = 1; a[n_] := a[n] = (n!)!/((n - 1)!)!;

%t Table[a[n], {n, 0, 6}]

%Y Cf. A000142.

%K nonn

%O 0,3

%A _Clark Kimberling_, Jul 16 2024