OFFSET
1,1
COMMENTS
A number 999...9998 will be a term if it has two prime factors 2 and 4999...999. Therefore 999999999999998 and 999...9998 (with 54 9's) are both terms. See A056712.
The next term is greater than 10^11.
LINKS
Michael S. Branicky, Table of n, a(n) for n = 1..40
EXAMPLE
77744411 is a term as 77744411 = 233 * 333667 which has distinct prime factors, 77744411 has nonincreasing digits while its prime factor concatenation "233333667" has nondecreasing digits.
PROG
(Python)
from sympy import factorint, isprime
from itertools import count, islice, combinations_with_replacement as mc
def nd(s): return s == "".join(sorted(s))
def bgen(d):
yield from ("".join(m) for m in mc("9876543210", d) if m[0]!="0")
def agen(): # generator of terms
for d in count(1):
out = set()
for s in bgen(d):
t = int(s)
if t < 4 or isprime(t): continue
f = factorint(t)
if len(f) < sum(f.values()): continue
if nd("".join(str(p) for p in f)):
out.add(t)
yield from sorted(out)
print(list(islice(agen(), 29))) # Michael S. Branicky, Apr 26 2024
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Scott R. Shannon, Apr 25 2024
EXTENSIONS
a(33)-a(38) from Michael S. Branicky, Apr 26 2024
STATUS
approved