%I #13 Nov 18 2023 11:55:10
%S 8,97,168,250,252,274,317,390,393,427,502,527,603,639,736,804,852,880,
%T 888,977,1048,1129,1220,1221,1232,1253,1284,1325,1376,1437,1508,1589,
%U 1680,1681,1692,1713,1744,1785,1836,1897,1968,2050,2052,2074,2116,2178,2260,2262,2284
%N Analog of A121805, but starting with 8.
%C Contains 198104936410 terms, the last being 9999999999972.
%H Michael De Vlieger, <a href="/A367352/b367352.txt">Table of n, a(n) for n = 1..10000</a>
%t b = 10; m = b - 1; a[1] = 8; a[n_] := a[n] = For[r = Mod[a[n - 1], b]; y = 0, y <= m, y++, If[y == IntegerDigits[#, b][[1]], Return[#]] &[a[n - 1] + b r + y]]; Array[a, 45] (* _Michael De Vlieger_, Nov 18 2023, after _Jean-François Alcover_ at A121805 *)
%o (Python)
%o from itertools import islice
%o def agen(start=8): # generator of terms
%o an, y = start, 1
%o while y < 10:
%o yield an
%o an, y = an + 10*(an%10), 1
%o while y < 10:
%o if str(an+y)[0] == str(y):
%o an += y
%o break
%o y += 1
%o print(list(islice(agen(), 50))) # _Michael S. Branicky_, Nov 18 2023
%Y Comma sequences in base 10, starting with 1, 2, 4, 5, 6, 7, 8, 9, 10 are A121805, A139284, A366492, A367337, A367350, A367351, A367352, A367353, A367354. Starting with 3 is trivial, and those starting with 11, 12, 13 are essentially duplicates.
%Y Cf. A330128, A330129.
%K nonn,fini,base
%O 1,1
%A _N. J. A. Sloane_, Nov 17 2023