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a(n) = (n^17 - n)/17.
4

%I #28 Nov 14 2023 16:35:55

%S 0,0,7710,7596480,1010580540,44878791360,995685849690,13684147881600,

%T 132458812569720,981010688215680,5882352941176470,29732178147017280,

%U 130506535690613940,508847995257725760,1793608631137129170,5795654431511374080,17361641481138401520

%N a(n) = (n^17 - n)/17.

%C See A366488 for further information.

%H Stefano Spezia, <a href="/A366490/b366490.txt">Table of n, a(n) for n = 0..10000</a>

%H Jack Jeffries, <a href="https://doi.org/10.1090/noti2833">Differentiating by prime numbers</a>, Notices Amer. Math. Soc., 70:11 (2023), 1772-1779.

%H <a href="/index/Rec#order_18">Index entries for linear recurrences with constant coefficients</a>, signature (18,-153,816,-3060,8568,-18564,31824,-43758,48620,-43758,31824,-18564,8568, -3060,816,-153,18,-1).

%F a(n) == 0 (mod 30), with 30 = A110936(primepi(17)). - _Hugo Pfoertner_, Nov 14 2023

%t A366490[n_]:=(n^17-n)/17;Array[A366490,30,0] (* _Paolo Xausa_, Nov 14 2023 *)

%Y Cf. A000217, A007290, A110936, A208536, A208537, A366488, A366489, A366491.

%K nonn,easy

%O 0,3

%A _N. J. A. Sloane_, Nov 13 2023