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A365936
Final digit (in decimal system) of n^(n-1) = A000169(n).
1
1, 2, 9, 4, 5, 6, 9, 2, 1, 0, 1, 8, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 9, 4, 5, 6, 9, 2, 1, 0, 1, 8, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 9, 4, 5, 6, 9, 2, 1, 0, 1, 8, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 9, 4, 5, 6, 9, 2, 1, 0, 1, 8, 1, 4, 5, 6, 1, 8, 1, 0, 1, 2, 9, 4, 5, 6, 9
OFFSET
1,2
COMMENTS
This is a periodic sequence with period 20 which is twice the considered radix.
LINKS
FORMULA
a(n) = n^(n-1) mod 10.
a(n) = A365935(n+10).
EXAMPLE
For n = 4, a(4) = 4^3 mod 10 = 64 mod 10 = 4.
MATHEMATICA
a[n_]:=Last[IntegerDigits[n^(n-1)]]; Array[a, 87] (* Stefano Spezia, Sep 26 2023 *)
CROSSREFS
KEYWORD
nonn,base,easy
AUTHOR
Marco Ripà, Sep 23 2023
STATUS
approved