OFFSET
1,5
COMMENTS
Smallest initial number k of n consecutive numbers satisfying bigomega(k) <= bigomega(k+1) <= ... <= bigomega(k+n-1).
EXAMPLE
a(5) = 121 = a(6) as bigomega(121) = bigomega(122) = bigomega(123) = 2 < bigomega(124) = bigomega(125) = 3 < bigomega(126) = 4.
MATHEMATICA
k = 1; Do[While[t = Table[PrimeOmega[i], {i, k, k + n - 1}]; t != Sort[t], k++]; Print[k], {n, 1, 10}]
PROG
(PARI) a(n) = my(k=1, list=List(vector(n, i, bigomega(i)))); while (vecsort(list) != list, listpop(list, 1); k++; listput(list, bigomega(k+n-1))); k; \\ Michel Marcus, Aug 14 2023
CROSSREFS
KEYWORD
nonn,more
AUTHOR
Ilya Gutkovskiy, Aug 08 2023
EXTENSIONS
a(11)-a(14) from Michel Marcus, Aug 14 2023
STATUS
approved