OFFSET
0,3
LINKS
Seiichi Manyama, Table of n, a(n) for n = 0..1000
FORMULA
a(n) = (1/(n+1)) * Sum_{k=0..n} binomial(n+1,k) * binomial(4*k,n-k).
PROG
(PARI) a(n) = sum(k=0, n, binomial(n+1, k)*binomial(4*k, n-k))/(n+1);
CROSSREFS
KEYWORD
nonn
AUTHOR
Seiichi Manyama, Aug 05 2023
STATUS
approved