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Index k of A007814(A000127(k)) at record terms.
1

%I #35 Sep 03 2023 10:30:29

%S 1,2,3,4,5,10,1034,1619,19940,151012,185354,937444,17714660,30594058,

%T 53467077,401540691,1127208901,34761279059,1529978475530,

%U 12645510928325

%N Index k of A007814(A000127(k)) at record terms.

%C For polynomial sequences like A000127 we can always find a recurrence formula, and with that you can show that all polynomial sequences mod m will be periodic. Terms of this sequence were found using A000127(k) mod 2^x, with a recursion formula, treating each k separately. This method limits the size of working quantities.

%C This sequence is related to the question: Is there a another power of 2 among Moser's circle numbers?

%H Burkard Polster, <a href="https://www.youtube.com/watch?v=4AuV93LOPcE">Why don't they teach Newton's calculus of 'What comes next?'</a>, YouTube video, Oct 02 2021.

%H Kevin Ryde, <a href="/A364133/a364133.gp.txt">PARI/GP Code</a>

%H Grant Sanderson, <a href="https://www.youtube.com/watch?v=YtkIWDE36qU">The absurd circle division pattern (updated) | Moser's circle problem</a>, YouTube video, Jul 02 2023.

%Y Cf. A000127, A007814.

%K nonn,more

%O 0,2

%A _Nicolas Bělohoubek_, Jul 10 2023