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A363833
Number of prime factors of A000129(n) (Pell numbers) (counted with multiplicity).
4
0, 1, 1, 3, 1, 3, 2, 5, 2, 3, 1, 7, 1, 4, 4, 7, 2, 5, 2, 7, 4, 4, 2, 10, 3, 4, 4, 8, 1, 9, 3, 9, 3, 5, 4, 12, 3, 4, 4, 11, 1, 9, 2, 9, 7, 5, 2, 14, 4, 6, 5, 8, 1, 8, 5, 11, 5, 3, 1, 17, 3, 6, 7, 13, 6, 8, 2, 10, 4, 9, 3, 17, 2, 7, 10, 10, 6, 10, 4, 15, 7, 5, 2
OFFSET
1,4
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..630 (calculated using Jon E. Schoenfield's a-file at A000129)
FORMULA
a(n) = bigomega(Pell(n)) = A001222(A000129(n)).
EXAMPLE
a(8)=5 because Pell(8)=408 has prime factors {2, 2, 2, 3, 17}.
MATHEMATICA
PrimeOmega[LinearRecurrence[{2, 1}, {1, 2}, 83]] (* Stefano Spezia, Oct 19 2023 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Tyler Busby, Oct 19 2023
STATUS
approved