allocate mem(2^30)

tr(v)=if (v>=0, 1+2*v, -2*v)

big = 1 000 000
s = 0
S = []
xS = []
unseen = 0
seen(v) = {
	v = tr(v);
	if (v < big,
		bittest(s, v),
		setsearch(S, v) || setsearch(xS, v)
	)
}
see(v) = {
	v = tr(v);
	if (v < big,
		s = bitor(s, 2^v),
		S = setunion(S, [v]);
		if (#S == 10 000,
			xS = setunion(xS, S);
			S = [];
		);
	);
	while (seen(unseen) && seen(-unseen),
		unseen++
	)
}

{
	for (n = 1, 2500,
		r = vector(n);

		v0 = unseen;
		while (1,
			if (!seen(v0),
				r[1] = v0;
				ok = 1;

				for (k=2, n,
					r[k] = -r[k-1]-p[k-1];
					if (seen(r[k]),
						ok = 0;
						break;
					);
				);

				if (ok && #Set(r)==n,
					apply (see, r);
					break;
				);
			);

			v0 = (v0<=0) - v0;
		);

		print (n " " r[1]);

		p = r;
	);
}

quit