OFFSET
2,2
LINKS
Seiichi Manyama, Table of n, a(n) for n = 2..50
FORMULA
Conjecture: a(n) = 6 *a(n-1) + a(n-2) - 20 * a(n-3) + 37 * a(n-4) + 16 * a(n-5) - 12 * a(n-6) - 7 * a(n-7) + 5 * a(n-8) - a(n-9) for n > 10.
CROSSREFS
KEYWORD
nonn
AUTHOR
Seiichi Manyama, Nov 27 2022
STATUS
approved