%I #20 Nov 06 2022 07:49:08
%S 1,110,1300,17000,790000,59900000,19999999000000,
%T 2999999999999990000000,4999999999999999999999999999900000000,
%U 899999999999999999999999999999999999999999999999999999999000000000
%N a(n) is the smallest primitive Niven number ending with n zeros.
%C 1 is a primitive Niven number, not ending with 0, so a(0)=1.
%C a(n) is the smallest term of A358255 that ends with n zeros for n > 0.
%H Giovanni Resta, <a href="https://www.numbersaplenty.com/set/Harshad_number/">Harshad numbers</a>.
%F a(n) = A051885(2^n)*10^n for n > 3. - _Rémy Sigrist_, Nov 05 2022
%e 1300 is divisible by 1+3=4, but 13 and 130 are not divisible by 4; 1300 is the smallest such integer ending with two 0's, so a(2) = 1300.
%Y Cf. A005349, A051885, A358255.
%K nonn,base
%O 0,2
%A _Bernard Schott_, Nov 05 2022