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a(n) is the least start of a run of n consecutive numbers whose abundancy index is larger than Pi^2/6.
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%I #5 Apr 26 2022 03:33:59

%S 4,44,188,8110374,330921744

%N a(n) is the least start of a run of n consecutive numbers whose abundancy index is larger than Pi^2/6.

%C By the Chinese Remainder Theorem, a(n) exists for all n. The proof is similar to the proof that is given for A094268.

%e a(1) = 4 since 4 is the least term of A353537.

%e a(2) = 44 since 44 is the least term of A353538.

%Y Cf. A000203, A013661, A094268.

%Y Cf. A353537, A353538, A353539, A353540, A353541.

%K nonn,more

%O 1,1

%A _Amiram Eldar_, Apr 25 2022