%I #5 Apr 26 2022 03:33:59
%S 4,44,188,8110374,330921744
%N a(n) is the least start of a run of n consecutive numbers whose abundancy index is larger than Pi^2/6.
%C By the Chinese Remainder Theorem, a(n) exists for all n. The proof is similar to the proof that is given for A094268.
%e a(1) = 4 since 4 is the least term of A353537.
%e a(2) = 44 since 44 is the least term of A353538.
%Y Cf. A000203, A013661, A094268.
%Y Cf. A353537, A353538, A353539, A353540, A353541.
%K nonn,more
%O 1,1
%A _Amiram Eldar_, Apr 25 2022