%I #26 May 12 2022 11:16:40
%S 0,7,13,18,22,25,27,35,43,51,59,67,75,83,91,99,107,115,123,131,139,147
%N Number of points available in a frame of snooker when there are n object balls remaining on the table.
%e For n=7 there are 35 points on the table.
%e 6 of these object balls are the non-reds and are worth a total of 27 points (2 for yellow, 3 for green, 4 for brown, 5 for blue, 6 for pink, 7 for black). The remaining red ball has a potential value of 8 points if its potting is followed by a potting of the black. 27 + 8 * 1 = 27 + 8 = 35
%t Table[If[n <= 15, 147 - 8*n, 27 - (n - 15)*(n - 12)/2], {n, 0, 21}] // Reverse (* _Vaclav Kotesovec_, May 04 2022, adapted to changed data May 11 2022 *)
%Y Cf. A180158, A128310, A241263.
%K nonn,fini,full
%O 0,2
%A _Stephen Cronin_, Apr 25 2022