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a(n) = A109812(A352205(n) + 1).
2

%I #7 Mar 29 2022 22:25:21

%S 1,2,8,24,64,160,448,896,2304,4608,11264,24576,53248,106496,245760,

%T 491520,1114112,2228224

%N a(n) = A109812(A352205(n) + 1).

%C a(n) is the term in A109812 immediately following the last n-bit term.

%C The values of a(n), written in base 2, with low-order bits on the left, are 1, 01, 0001, 00011, 0000001, 00000101, 000000111, 0000000111, 000000001001, 0000000001001, 00000000001101, 000000000000011, 0000000000001011, 00000000000001011, 000000000000001111, 0000000000000001111, 000000000000000010001, 0000000000000000010001, ... It would be nice to know exactly what the pattern is.

%Y Cf. A109812, A305370, A352203, A352204, A352205.

%K nonn,more

%O 0,2

%A _N. J. A. Sloane_ and _Chai Wah Wu_, Mar 29 2022