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%I #7 Feb 25 2022 21:20:27
%S 1,1,2,129,297233651245505,
%T 1588898389043626055434220300433167237829218942966252641093888571632886068535351219199489258571766594
%N a(1) = a(2) = 1; for n >= 2, a(n+1) = (a(n)^7 + 1)/a(n-1).
%C a(7) has 680 digits.
%p a:=proc(n) option remember: if n <= 2 then 1: else (a(n-1)^7+1)/a(n-2): fi: end:
%Y Cf. A076839, A003819, A003818, A003821.
%K nonn
%O 1,3
%A _Robert Dougherty-Bliss_, Feb 25 2022