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A351257
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Least k such that the k-th arithmetic derivative of A351255(n) is zero.
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8
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1, 2, 2, 3, 4, 5, 2, 3, 3, 4, 5, 6, 5, 6, 2, 5, 4, 3, 4, 3, 3, 4, 5, 4, 4, 7, 12, 6, 7, 4, 4, 4, 4, 4, 4, 4, 5, 8, 8, 6, 5, 12, 5, 5, 5, 8, 10, 6, 6, 6, 7, 6, 7, 7, 8, 12, 8, 12, 2, 3, 6, 3, 3, 4, 4, 5, 4, 4, 4, 8, 5, 5, 6, 12, 6, 3, 3, 7, 3, 3, 10, 3, 4, 5, 5, 4, 4, 6, 4, 4, 4, 6, 5, 5, 6, 5, 9, 5, 6, 10, 7, 7, 7
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OFFSET
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1,2
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COMMENTS
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a(n) is the number of iterations of the map x -> A003415(x) needed to reach zero, when starting from x = A351255(n).
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LINKS
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FORMULA
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EXAMPLE
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From A351255(27) = 2625 it takes 12 iterations of map x -> A003415(x) to reach zero, as 2625 -> 2825 -> 1155 -> 886 -> 445 -> 94 -> 49 -> 14 -> 9 -> 6 -> 5 -> 1 -> 0, therefore a(27) = 12.
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PROG
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(PARI)
A003415checked(n) = if(n<=1, 0, my(f=factor(n), s=0); for(i=1, #f~, if(f[i, 2]>=f[i, 1], return(0), s += f[i, 2]/f[i, 1])); (n*s));
A099307(n) = { my(s=1); while(n>1, n = A003415checked(n); s++); if(n, s, 0); };
A276086(n) = { my(m=1, p=2); while(n, m *= (p^(n%p)); n = n\p; p = nextprime(1+p)); (m); };
for(n=0, 2^9, u=A276086(n); c = A099307(u); if(c>0, print1(c, ", ")));
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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