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A350015
Irregular triangle read by rows: T(n,k) is the number of n-permutations whose third-longest cycle has length exactly k; n >= 0, 0 <= k <= floor(n/3).
7
1, 1, 2, 5, 1, 17, 7, 74, 46, 394, 311, 15, 2484, 2241, 315, 18108, 17627, 4585, 149904, 152839, 57897, 2240, 1389456, 1460944, 705600, 72800, 14257440, 15326180, 8673060, 1660120, 160460640, 175421214, 110271546, 31600800, 1247400, 1965444480, 2177730270, 1469308698, 559402272, 55135080
OFFSET
0,3
COMMENTS
If the permutation has no third cycle, then its third-longest cycle is defined to have length 0.
LINKS
Steven Finch, Second best, Third worst, Fourth in line, arxiv:2202.07621 [math.CO], 2022.
FORMULA
Sum_{k=0..floor(n/3)} k * T(n,k) = A332852(n) for n >= 3. - Alois P. Heinz, Dec 12 2021
EXAMPLE
Triangle begins:
[0] 1;
[1] 1;
[2] 2;
[3] 5, 1;
[4] 17, 7;
[5] 74, 46;
[6] 394, 311, 15;
[7] 2484, 2241, 315;
[8] 18108, 17627, 4585;
[9] 149904, 152839, 57897, 2240;
...
MAPLE
b:= proc(n, l) option remember; `if`(n=0, x^l[1], add((j-1)!*
b(n-j, sort([l[], j])[2..4])*binomial(n-1, j-1), j=1..n))
end:
T:= n-> (p-> seq(coeff(p, x, i), i=0..degree(p)))(b(n, [0$3])):
seq(lprint(T(n)), n=0..14); # Alois P. Heinz, Dec 11 2021
MATHEMATICA
b[n_, l_] := b[n, l] = If[n == 0, x^l[[1]], Sum[(j - 1)!*b[n - j, Sort[Append[l, j]][[2 ;; 4]]]*Binomial[n - 1, j - 1], {j, 1, n}]];
T[n_] := With[{p = b[n, {0, 0, 0}]}, Table[Coefficient[p, x, i], {i, 0, Exponent[p, x]}]];
Table[T[n], {n, 0, 14}] // Flatten (* Jean-François Alcover, Dec 28 2021, after Alois P. Heinz *)
CROSSREFS
Column 0 gives 1 together with A000774.
Row sums give A000142.
Sequence in context: A352010 A350016 A162975 * A187244 A120294 A186766
KEYWORD
nonn,tabf
AUTHOR
Steven Finch, Dec 08 2021
STATUS
approved