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%I #9 May 10 2024 02:26:54
%S 57,58,60,61,63,64,66,67,69,70,71,72,73,74,75,76,77,78,79,80,81,82,83,
%T 84,85,86,87,88,89,90,91,92,93,94,95,96,97,98,99,100,101,102,103,104,
%U 105,106,107,108,109,110,111,112,113,114,115,116,117,118,119,120
%N Numbers that are the sum of ten squares in seven or more ways.
%H Sean A. Irvine, <a href="/A346806/b346806.txt">Table of n, a(n) for n = 1..10000</a>
%e 58 = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 7^2
%e = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 5^2 + 5^2
%e = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 2^2 + 2^2 + 2^2 + 4^2 + 5^2
%e = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 3^2 + 3^2 + 3^2 + 5^2
%e = 1^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 5^2
%e = 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 1^2 + 2^2 + 4^2 + 4^2 + 4^2
%e = 1^2 + 1^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 2^2 + 4^2 + 4^2
%e = 1^2 + 1^2 + 1^2 + 2^2 + 2^2 + 2^2 + 3^2 + 3^2 + 3^2 + 4^2
%e = 1^2 + 1^2 + 1^2 + 1^2 + 3^2 + 3^2 + 3^2 + 3^2 + 3^2 + 3^2
%e so 58 is a term.
%o (Python)
%o from itertools import combinations_with_replacement as cwr
%o from collections import defaultdict
%o keep = defaultdict(lambda: 0)
%o power_terms = [x**2 for x in range(1, 1000)]
%o for pos in cwr(power_terms, 10):
%o tot = sum(pos)
%o keep[tot] += 1
%o rets = sorted([k for k, v in keep.items() if v >= 7])
%o for x in range(len(rets)):
%o print(rets[x])
%Y Cf. A345504, A345555, A346805, A346807.
%K nonn
%O 1,1
%A _David Consiglio, Jr._, Aug 04 2021