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a(n) = number of runs in n-th word in A342910.
1

%I #4 Jun 07 2021 10:41:05

%S 1,1,1,2,2,1,2,1,3,1,2,2,2,3,3,1,2,3,2,2,2,4,3,3,1,1,3,3,4,2,3,2,2,4,

%T 2,4,3,3,1,2,3,3,3,3,5,2,4,3,3,2,2,4,2,3,4,4,3,4,3,1,2,2,4,3,3,3,4,5,

%U 5,2,3,5,3,4,3,3,2,2,4,1,3,3,4,4,5,4

%N a(n) = number of runs in n-th word in A342910.

%e The first 20 words in A342910: 0, 1, 00, 01, 10, 000, 001, 11, 010, 0000, 100, 0001, 011, 101, 0010, 00000, 110, 0100, 00001, 1000; so a(9) = 3, the runs being 0, 1, and 9..

%t (See A342910.)

%Y Cf. A342910, A342789.

%K nonn,base

%O 1,4

%A _Clark Kimberling_, Jun 03 2021