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A341623
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Numbers k such that sigma(3*k) = 8*k.
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1
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OFFSET
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1,1
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COMMENTS
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Every perfect number P greater than 6 (so, P is not divisible by 3) will be found in this sequence. Proof: sigma(3*P) = sigma(3)*sigma(P) = 4*(2*P) = 8*P. - Timothy L. Tiffin, Aug 26 2021
Solutions are integers y/3 where sigma(y)/y = 8/3. - Michel Marcus, Aug 27 2021
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LINKS
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EXAMPLE
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546 is a term, since sigma(3*546) = sigma(1638) = 4368 = 8*546. - Timothy L. Tiffin, Aug 26 2021
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MATHEMATICA
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Select[Range[5*10^9], DivisorSigma[1, 3*#] == 8*# &] (* Timothy L. Tiffin, Aug 26 2021 *)
Do[If[DivisorSigma[1, 3*k] == 8*k, Print[k]], {k, 5*10^9}] (* Timothy L. Tiffin, Aug 26 2021 *)
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CROSSREFS
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Cf. A000396 (subsequence, apart from its terms that are divisible by 3).
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KEYWORD
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nonn,more
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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