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A340540
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Number of walks of length 4n in the first octant using steps (1,1,1), (-1,0,0), (0,-1,0), and (0,0,-1) that start and end at the origin.
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2
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1, 6, 288, 24444, 2738592, 361998432, 53414223552, 8525232846072, 1443209364298944, 255769050813120576, 47020653859202576640, 8907614785269428079168, 1730208409741026141405696, 343266632435192859791576064, 69350551439109880798294334208
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OFFSET
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0,2
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COMMENTS
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There are no such walks with length that is not a multiple of 4.
a(n) is also the number of arrangements of n copies each of "a", "b", "c", and "d" such that no prefix has more b's, c's, or d's than a's.
The analogous problem in dimensions 1 and 2 are given respectively by A000108 (the Catalan numbers) and A006335.
No closed form is known. In fact, it is not known whether this sequence is D-finite (see Bacher et al.).
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LINKS
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MAPLE
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b:= proc(n, l) option remember; `if`(n=0, 1, `if`(add(i, i=l)+3<n,
b(n-1, map(x-> x+1, l)), 0) +add(`if`(l[i]>0,
b(n-1, sort(subsop(i=l[i]-1, l))), 0), i=1..3))
end:
a:= n-> b(4*n, [0$3]):
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MATHEMATICA
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b[n_, l_] := b[n, l] = If[n == 0, 1, If[Total[l] + 3 < n,
b[n-1, l+1]], 0] + Sum[If[l[[i]] > 0,
b[n-1, Sort[ReplacePart[l, i -> l[[i]]-1]]], 0], {i, 1, 3}] /. Null -> 0;
a[n_] := b[4n, {0, 0, 0}];
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PROG
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(Python)
import itertools as it
i = 0
while 1:
counts = {(a, b, c):0 for a, b, c in it.product(range(i+1), repeat=3)}
counts[0, 0, 0] = 1
for _ in range(4*i):
update = {(a, b, c):0 for a, b, c in it.product(range(i+1), repeat=3)}
for x, y, z in counts:
if counts[x, y, z] != 0:
for coord in [(x+1, y+1, z+1), (x-1, y, z), (x, y-1, z), (x, y, z-1)]:
if coord in update:
update[coord] += counts[x, y, z]
counts = update
print(i, counts[0, 0, 0])
i += 1
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CROSSREFS
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KEYWORD
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nonn,walk
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AUTHOR
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STATUS
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approved
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