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A339790
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First coefficient of the lindep transform of sigma(n).
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3
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1, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1, 1, 2, 3, 1, 2, 1, 2, 2, 1, 1, 2, 1, 1, 2, 2, 3, 2, 1, 2, 2, 4, 1, 3, 1, 1, 4, 2, 1, 2, 1, 1, 5, 1, 1, 4, 3, 1, 5, 2, 1, 1, 1, 2, 3, 1, 3, 1, 1, 1, 5, 1, 1, 3, 1, 2, 3, 1, 4, 1, 1, 3, 2, 2, 1, 3, 4, 2, 5, 1, 1, 5, 4, 6, 3, 2, 4, 3, 1, 4, 7, 6
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OFFSET
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1,9
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COMMENTS
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If {b(n)} is a sequence of integers, we will call the "lindep transform" of {b(n)} the triplet of sequences ({x(n)}, {y(n)}, {z(n)}) such that:
(i) x(n) >= 1
(ii) x(n) + abs(y(n)) + abs(z(n)) is minimal
(iii) x(n)*b(n) + y(n)*n + z(n) = 0
(iv) if with the conditions (i), (ii), (iii) there exist several triplets (x(n), y(n), z(n)) we then choose the one with minimal y(n).
We call x(n) the first coefficient of the lindep transform of b(n), y(n) the second and z(n) the third. As this corresponds to the lindep function of PARI/GP this transform is called the "lindep transform".
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LINKS
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FORMULA
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Conjecture: a(n) << sqrt(n) with 0 < limsup n->oo a(n)/sqrt(n) < oo exists (see graphic). Trivially liminf a(n)/sqrt(n) = 0 since for prime n we have a(n)=1.
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PROG
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(PARI) a(n)=(lindep([sigma(n), n, 1])*sign(lindep([sigma(n), n, 1])[1]))[1]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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