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A337610
Positive integers m such that A126287^k(m) = m for some positive integer k.
4
1, 10, 15, 22, 26, 33, 34, 46, 51, 58, 65, 69, 70, 82, 86, 87, 94, 105, 106, 118, 122, 123, 130, 134, 141, 142, 146, 154, 159, 166, 177, 178, 190, 195, 202, 206, 213, 214, 215, 218, 226, 231, 238, 249, 250, 254, 262, 266, 267, 274, 285, 286, 298, 302, 303, 310
OFFSET
1,2
COMMENTS
A126287^k(m) means apply A126287 to m k times.
Equivalently, the numbers that belong to a cycle under the map x -> A126287(x).
For any term m in this sequence, A126287(A126287(m)) = m.
Supersequence of A017641. Moreover, this sequence (excluding the first term) can be represented as an infinite union of arithmetic progressions.
There are no primes in this sequence.
EXAMPLE
10 is a term since A126287(A126287(10)) = A126287(15) = 10.
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Ely Golden, Oct 07 2020
STATUS
approved