OFFSET
0,2
COMMENTS
Can we prove m is a divisor for all terms a(n) for n > N for some n? For example, are all terms from a(1) onwards divisible by 2?
For n > 0, it seems that 6|a(n) and a(n) is a Zumkeller number (A083207). Verified for n up to and including 29. - Ivan N. Ianakiev, Aug 02 2020
EXAMPLE
a(3) = 60060 as 60060 = 28 * 39 * 55 = 33 * 35 * 52 = 35 * 39 * 44 and no positive integer < 60060 has exactly 3 such triples.
CROSSREFS
KEYWORD
nonn
AUTHOR
David A. Corneth, Jul 28 2020
STATUS
approved