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A335253
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Numbers k such that the abundance (A033880) of k is equal to the deficiency (A033879) of k+2.
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1
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12, 76, 488, 556, 1100, 1430, 2408, 8896, 538208, 13685780, 962402768
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OFFSET
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1,1
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COMMENTS
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Equivalently, k and k+2 have the same absolute value of abundance (or deficiency) with opposite signs.
Equivalently, s(k) + s(k+2) = k + (k+2), where s(k) is the sum of proper divisors of k (A001065).
a(12) > 10^11, if it exists.
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LINKS
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EXAMPLE
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12 is a term since A033880(12) = sigma(12) - 2*12 = 28 - 24 = 4, and A033879(14) = 2*14 - sigma(14) = 28 - 24 = 4.
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MATHEMATICA
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ab[n_] := DivisorSigma[1, n] - 2*n; Select[Range[10^5], ab[#] == -ab[# + 2] &]
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PROG
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(PARI) isok(k) = sigma(k) + sigma(k+2) == 4*k+4; \\ Michel Marcus, May 29 2020
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CROSSREFS
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KEYWORD
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nonn,more
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AUTHOR
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STATUS
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approved
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