login
a(n) = nim-product of 2^3 and 2^n.
2

%I #17 Jun 12 2020 12:24:29

%S 8,12,11,13,128,192,176,208,2048,3072,2816,3328,32768,49152,45056,

%T 53248,524288,786432,720896,851968,8388608,12582912,11534336,13631488,

%U 134217728,201326592,184549376,218103808,2147483648,3221225472,2952790016,3489660928

%N a(n) = nim-product of 2^3 and 2^n.

%H Rémy Sigrist, <a href="/A335160/b335160.txt">Table of n, a(n) for n = 0..1000</a>

%H J. H. Conway, <a href="https://doi.org/10.1016/0012-365X(90)90008-6">Integral lexicographic codes</a>, Discrete Mathematics 83.2-3 (1990): 219-235. See Table 4.

%F Conjectures from _Colin Barker_, Jun 11 2020: (Start)

%F G.f.: (8 + 12*x + 11*x^2 + 13*x^3) / ((1 - 2*x)*(1 + 2*x)*(1 + 4*x^2)).

%F a(n) = 16*a(n-4) for n>3.

%F (End)

%Y Row 3 of array in A223541.

%K nonn

%O 0,1

%A _N. J. A. Sloane_, Jun 08 2020.

%E More terms from _Rémy Sigrist_, Jun 10 2020