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A330894
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Numbers of Pythagorean quadruples contained in the divisors of A330893(n).
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5
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1, 1, 2, 2, 2, 1, 3, 1, 3, 2, 4, 3, 2, 2, 1, 4, 1, 2, 3, 2, 7, 4, 2, 2, 8, 2, 1, 4, 4, 2, 3, 7, 3, 2, 5, 2, 2, 4, 6, 2, 5, 2, 11, 6, 4, 1, 4, 1, 6, 2, 4, 12, 2, 5, 1, 4, 6, 4, 2, 5, 6, 4, 1, 2, 3, 4, 17, 6, 2, 3, 6, 1, 5, 6, 1, 3, 4, 6, 6, 13, 1, 2, 4, 8, 4, 4
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OFFSET
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1,3
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LINKS
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EXAMPLE
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a(7) = 3 because A330893(7)=168, and the set of divisors of 168: {1, 2, 3, 4, 6, 7, 8, 12, 14, 21, 24, 28, 42, 56, 84, 168} contains three Pythagorean quadruples {2, 3, 6, 7}, {4, 6, 12, 14} and {8, 12, 24, 28}.
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MAPLE
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with(numtheory):
for n from 3 to 1700 do :
d:=divisors(n):n0:=nops(d):it:=0:
for i from 1 to n0-3 do:
for j from i+1 to n0-2 do :
for k from j+1 to n0-1 do:
for m from k+1 to n0 do:
if d[i]^2 + d[j]^2 + d[k]^2 = d[m]^2
then
it:=it+1:
else
fi:
od:
od:
od:
od:
if it>0 then
printf(`%d, `, it):
else fi:
od:
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MATHEMATICA
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nq[n_] := If[Mod[n, 6] > 0, 0, Block[{t, u, v, c = 0, d = Divisors[n], m}, m = Length@ d; Do[t = d[[i]]^2 + d[[j]]^2; Do[u = t + d[[h]]^2; If[u > n^2, Break[]]; If[Mod[n^2, u] == 0 && IntegerQ[v = Sqrt@ u] && Mod[n, v] == 0, c++], {h, j+1, m-1}], {i, m-3}, {j, i+1, m - 2}]; c]]; Select[Array[nq, 1638], # > 0 &] (* Giovanni Resta, May 04 2020 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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