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a(n) = A329638(A324201(n)).
3

%I #7 Nov 22 2019 18:54:00

%S 1,5,269,6181,42467605,6698339765,137657144245,2482519341068581109,

%T 4650094754920132605500516092412538533,

%U 172211278811469777927840379819793091108558586157350885,6181597550035473098411130103418930148893343460909707255358224869,15429082227467244202811178054212231454083499413948013030392138990797549495221

%N a(n) = A329638(A324201(n)).

%C The first 12 terms are all squarefree (in A005117). Does this hold in general?

%F a(n) = A329638(A324201(n)) = A329639(A324201(n)) = A329641(A324201(n)).

%Y Cf. A000043, A005117, A324201, A329638, A329639, A329641, A329644.

%K nonn

%O 1,2

%A _Antti Karttunen_, Nov 22 2019