OFFSET
1,1
COMMENTS
Grundman found a(1) and proved that there are no runs of 5 consecutive lazy-Fibonacci-Niven numbers.
LINKS
Amiram Eldar, Table of n, a(n) for n = 1..72
Helen G. Grundman, Consecutive Zeckendorf-Niven and lazy-Fibonacci-Niven numbers, Fibonacci Quarterly, Vol. 45, No. 3 (2007), pp. 272-276.
EXAMPLE
MATHEMATICA
ooQ[n_] := Module[{k = n}, While[k > 3, If[Divisible[k, 4], Return[True], k = Quotient[k, 2]]]; False]; c = 0; cn = 0; k = 1; s = {}; v = Table[-1, {4}]; While[cn < 10, If[! ooQ[k], c++; d = Total@IntegerDigits[k, 2]; If[Divisible[c, d], v = Join[Rest[v], {c}]; If[AllTrue[Differences[v], # == 1 &], cn++; AppendTo[s, c - 3]]]]; k++]; s
CROSSREFS
KEYWORD
nonn
AUTHOR
Amiram Eldar, Oct 07 2019
EXTENSIONS
More terms from Amiram Eldar, Oct 23 2019
STATUS
approved