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A327802
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Number of primes p such that n < p < (9/8) * n.
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3
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0, 0, 0, 0, 0, 0, 0, 0, 0, 1, 0, 1, 0, 0, 0, 1, 1, 1, 0, 0, 1, 1, 0, 0, 0, 1, 1, 2, 1, 1, 0, 0, 1, 1, 1, 1, 1, 1, 2, 2, 1, 2, 1, 1, 1, 1, 0, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 1, 2, 1, 1, 1, 2, 3, 3, 2, 2, 2, 2, 2, 2, 1, 2, 2, 2, 2, 2, 1, 2, 2, 2, 1, 1, 1, 1, 2, 2, 1, 2, 2, 3, 3, 3, 3, 4, 4, 4, 4, 4, 4, 4, 3, 3, 3
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OFFSET
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1,28
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COMMENTS
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In 1932, Robert Hermann Breusch proved that for n > 47 there is at least one prime p between n and (9/8)*n. This was an improvement of Bertrand's postulate also called Chebyshev's theorem: if n > 1, there is always at least one prime p such that n < p < 2*n.
a(n) = 0 for 1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 13, 14, 15, 19, 20, 23, 24, 25, 31, 32, 47; the terms of A285586 correspond to the inequality n <= p <= (9/8) * n.
Records for a(n) = 0, 1, 2, 3, 4, ... are obtained for n = 1, 10, 28, 65, 96, ...
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REFERENCES
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François Le Lionnais, Jean Brette, Les Nombres remarquables, Hermann, 1983, nombre 48, page 46.
David Wells, The Penguin Dictionary of Curious and Interesting Numbers (Revised Edition), Penguin Books, 1997, entry 48, page 106.
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LINKS
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FORMULA
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EXAMPLE
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9/8 * 17 = 19.125 and between 17 and 19.125, only 19 is a prime hence a(17) = 1.
9/8 * 39 = 43.875, and between 39 and 43.875, there are 41 and 43 that are primes hence a(39) = 2.
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MATHEMATICA
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Table[PrimePi[(9/8)*n] - PrimePi[n], {n, 1, 80}] (* Metin Sariyar, Sep 26 2019 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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