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A327614
Number of transfers of marbles between four sets until the first repetition.
2
4, 5, 10, 11, 12, 12, 12, 10, 15, 17, 12, 12, 12, 15, 17, 16, 16, 15, 19, 17, 17, 15, 15, 19, 22, 17, 16, 15, 19, 22, 21, 19, 19, 24, 26, 21, 19, 19, 24, 26, 21, 19, 19, 24, 26, 21, 19, 23, 28, 26, 21, 19, 23, 28, 26, 21, 19, 23, 28, 26, 21, 19, 23, 28
OFFSET
1,1
COMMENTS
There are initially n marbles in each of the four sets. In the first turn, half of the marbles of set A are transferred to set B, rounding to the upper integer when halving. In the second turn, half of the marbles of set B are transferred to set C, following the same rule. The game goes on back on following the pattern (A to B), (B to C), (C to D), (D to A) etc. until we reach a distribution already encountered.
a(n) is then the number of steps until the first repetition occurs.
The indexes of the maximal values are 1, 2, 3, 4, 5, 9, 10, 19, 25, 34, 35, 49, 105, 194, 330, 334, 480, 1553, 1780, 2834, 2870, 4079, ...
EXAMPLE
For n = 2, (SetA ; SetB ; SetC ; SetD):
(2 ; 2 ; 2 ; 2), ceiling(2/2)=1 marble get transferred from SetA to SetB,
(1 ; 3 ; 2 ; 2), ceiling(3/2)=2 marbles get transferred from SetB to SetC,
(1 ; 1 ; 4 ; 2), ceiling(4/2)=2 marbles get transferred from SetC to SetD,
(1 ; 1 ; 2 ; 4), ceiling(4/2)=2 marbles get transferred from SetD to SetA,
(3 ; 1 ; 2 ; 2), ceiling(3/2)=2 marbles get transferred from SetA to SetB,
(1 ; 3 ; 2 ; 2), this is a repetition, it took 5 steps to get there, so a(2) = 5.
For n = 4, (SetA ; SetB ; SetC ; SetD):
(4 ; 4 ; 4 ; 4), (2 ; 6 ; 4 ; 4), (2 ; 3 ; 7 ;4), (2 ; 3 ; 3 ; 8), (6 ; 3 ; 3 ; 4), (3 ; 6 ; 3 ; 4), (3 ; 3 ; 6 ; 4), (3 ; 3 ; 3 ; 7), (7 ; 3 ; 3 ; 3), (3 ; 7 ; 3 ; 3), (3 ; 3 ; 7 ; 3), (3 ; 3 ; 3 ; 7) which is a repetition, so a(4) = 11.
CROSSREFS
Cf. A327565 (two sets), A327613 (three sets).
Sequence in context: A263828 A327577 A092961 * A177711 A115945 A092027
KEYWORD
nonn
AUTHOR
Tristan Cam, Sep 19 2019
STATUS
approved